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Bab Logaritma
Matematika SMA Kelas X

2 log x + log 6x - log 2x - log 27 = 0
log (x² . 6x / (2x . 27)) = 0
x²/9 = 10⁰
x² = 9 . 1
x² - 9 = 0
(x + 3) (x - 3) = 0
x + 3 = 0
x = -3

x - 3 = 0
x = 3

syarat
2x > 0
x > 0

Maka, x = 3

Jawabannya A

2 log x + log6x - log2x - log27 = 0
2 logx + log(3 . 2 . x) - log(2 . x) - log3³ = 0
2 logx + log3 + log2 + logx - log2 - logx - 3 log3 = 0
2 logx - 2 log3 = 0
logx = log3
log3 / logx = 1
ˣlog3 = 1
x = 3