butuh banget,pake cara yaaaaa,terimakasih

22222222222222222222222222222222222222222

jawab
23. f(x) = 6/(x+3)
g(x)= x²

fog(x) = 6/(x²+ 3)
y = 6/(x²+3)
x² y + 3y = 6
x² = (6 - 3y)/y
x = √{(6 - 3y)/y}
(fog)⁻¹(x) = √{(6- 3x)/(x)}
domain  6- 3x/ x ≥ 0 dengan x ≠ 0
(6-3x)(x) ≥ 0

6-3x = 0 atau x = 0
x= 2 atau x = 0
garis bilangan

..(-)...(0)...(+)...(2)..(-)....
hp  0 ≤ x ≤ 2 n x ≠ 0
maka
HP  0 < x ≤ 2

24)
f(x) = 3/x
g(x) = x²
(fog)⁻¹(3)=

fog(x) = 3/x²
(fog)⁻¹ (3/x²) = x
3/x² = 3
3x² = 3
x = 1 atau x = - 1
untuk x > 0 maka  (fog)⁻¹ (3)= 1


25) f⁻¹(3)= 1 → f(1)= 3
f(x) = (mx -5)/(3x+2)
x = 1 → (mx -5)/(3x+2)= 3
{m(1) - 5} / {3.1+2} = 3
m- 5 / 5 = 3
m -5 = 3(5) = 15
m = 20