1.selesaikan sistim persamaan berikut dengan menggunakan subtitusi a.2x-3y=5 dan 4x-y=3 b.2x+10y=14 dan 5x-9y=1, 2. selesaikan sisitim persamaan berikut dengan

1a) 2x - 3y = 5
2x = 3y + 5
disubtitusi ke pers :
4x - y = 3
(2•2x) - y = 3
2(3y + 5) - y = 3
6y + 10 - y = 3
5y = 3 - 10
5y = - 7
y = - 7/5
disubtitusi ke pers :
2x = 3y + 5
2x = 3(-7/5) + 5
2x = - 21/5 + 25/5
2x = 4/5
x = 4/5 ÷ 2
x = 4/10
x = 2/5
hp = { 2/5 , - 7/5 }

b) 2x + 10y = 14
2x = - 10y + 14
x = - 5y + 7
disubtitusi ke pers :
5x - 9y = 1
5(-5y + 7) - 9y = 1
- 25y + 35 - 9y = 1
- 25 - 9y = 1 - 35
- 34y = - 34
y = 1
disubtitusi ke pers :
x = - 5y + 7
x = - 5(1) + 7
x = - 5 + 7
x = 2
hp = { 2 , 1 }

2) y = x - 4
y - x = - 4
y = 4x - 10
y - 4x = - 10

maka
y - x = - 4
y - 4x = - 10
-----------------(-)
3x = 6
x = 2

y - x = - 4 |×4
y - 4x = - 10
maka
4y - 4x = - 16
y - 4x = - 10
--------------------(-)
3y = - 6
y = - 2
hp = { 2 , -2 }

b) x = 2y + 7
x - 2y = 7
3x - 2y = 3
------------------(-)
- 2x = 4
x = - 2

x - 2y = 7 |×3
3x - 2y = 3
maka
3x - 6y = 21
3x - 2y = 3
------------------(-)
- 4y = 18
y = - 18/4
hp = { - 2 , - 18/4 }