diketahui penyelesaian persamaan ^2log^2 (x+2)+^2log(x+2)^3=^2log1/4 adalah x1 dan x2.nilai x1x2 adalah

^2Log^2(x+2) + ^2log(x+2)^3 = ^2Log1/4
(^2Log(x+2))^2 + 3 ^2Log(x+2) = -2
Mis : y = ^2Log(x+2)
y^2 + 3y + 2 = 0
(y + 2)(y + 1)
y = -2 atau y = -1
utk y = -2
-2 = ^2Log(x+2)
^2Log2^-2 = ^2Log(x+2)
x + 2 = 1/4
x = 1/4 - 2 = 1/4 - 8/4 = -7/4

utk y = -1
x + 1 = 1/2
x = 1/2 - 1 = -1/2

Jadi, x1x2 = (-7/4)(-1/2) = 7/8