Diketahui :f(x)=3-x dan g(x)=(x+2)² Ditanya : (fog)(x) dan (gof)(x) Fungsi Komposisi

(f • g)(x) = f(gx)
= 3 - x
= 3 - (x + 2)²
= - x² - 4x + 1

(g • f)(x) = g(fx)
= (x + 2)²
= ( 3 - x + 2)²
= ( 5 - x )²
= 25 - 10x + x²
= x² - 10x + 25