diketahui penyelesaian persamaan ²log²(x + 2)+²log(x + 2)³= ²log¼ adalah X1 dan X2.nilai x1x2=...

²log²(x + 2) + ²log(x + 2)³ =  ²log¼
²log²(x + 2) + 3.²log(x + 2) =  ²log2⁻²
syarat
x + 2 > 0
x > -2

Misalkan
y = ²log(x + 2)

maka
y² + 3y = -2
y² + 3y + 2 = 0
(y + 2)(y + 1) = 0
y = -2 atau  y = -1

y = - 2
²log(x + 2) = -2
²log(x + 2) = ²log2⁻²
x + 2 = 2⁻²
x + 2 = 1/4
x = 1/4 - 8/4
x = -7/4

y = -1
²log(x + 2) = -2
²log(x + 2) = ²log2⁻¹
x + 2 = 2⁻¹
x = 1/2 - 4/2
x = -3/2

x1 . x2
= (-7/4)(-3/2)
= 21/8