Diletahui luas CDEF 90 cm2dan panjang CE =15 cm .luas abcd.....cm2

90×2÷15=12cm
12÷2=6 cm
6×10÷2=30cm2
10×(8+6)=140cm2
140+30=170cm2 (b)

d1 x d2 / 2
-> 15 x a = 90
->         a = 90/15
->         a = 6 cm (FD)

-> FG = 6/2
-> FG = 3
-> AG = BC
-> AG = AF + BC
-> AG = 8 + 3 = 11
-> BC = 11 cm
-> AD = 8 + 6 = 14 cm

a+b /2 x t
-> 14 + 11 / 2 x 10
-> 25 / 2 x 10
-> 12,5 x 10 = 125 cm²
(gaada jawabannya. Maap klo salah, smg membantu aja)