Matematika

Pertanyaan

sin
[tex] \sin(\pi + x) \sin(\pi + x) [/tex]
(pi + x) sin (pi-x)

1 Jawaban

  • Materi : Trigonometri



    -2 sinα sinβ = cos(α+β) - cos(α-β)
    sinα sinβ = 1/2( cos(α-β) - cos(α+β) )

    cos2α = 1 - 2 sin²α
    sin²α = 1/2 (1 - cos2α)

    π + x + π - x = 2π
    π + x - π + x = 2x

    sin(π + x) sin(π - x)
    = 1/2 ( cos(2x) - cos(2π) )
    = 1/2 (cos2x -  1)
    = -sin²x

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