H:x -> \frac{1}{3} (x-4) a.F(2) b.(-2)

[tex]f(x)= \frac{1}{3}(x-4) \\ f(2)= \frac{1}{3}(2-4) =\frac{1}{3}(-2) =- \frac{3}{2} \\ f(-2)=\frac{1}{3}(-2-4) =\frac{1}{3}(-6) =-2[/tex]