Matematika

Pertanyaan

ada yg bisa jawab ngak?tolong dibantu ya :) makasih
ada yg bisa jawab ngak?tolong dibantu ya :) makasih

1 Jawaban

  • 1) x - y = 4
    2x + y = 8
    ---------------(+)
    3x = 12
    x = 4
    disubstitusi ke pers :
    x - y = 4
    4 - y = 4
    - y = 4 - 4
    y = 0
    hp = { 4,0} ( D )

    2) 2x + 3y = 15 |×2
    4x - y = - 19
    maka
    4x + 6y = 30
    4x - y = - 19
    ------------------(-)
    7y = 49
    y = 7
    disubstitusi ke pers :
    2x + 3y = 15
    2x + 3(7) = 15
    2x + 21 = 15
    2x = 15 - 21
    2x = - 6
    x = - 3
    hp = { - 3 , 7 } ( B )

    3) 3x + y = - 1 |×3
    x + 3y = 5
    maka
    9x + 3y = - 3
    x + 3y = 5
    --------------------(-)
    8x = - 8
    x = - 1
    disubstitusi ke pers
    3x + y = - 1
    3(-1) + y = - 1
    - 3 + y = - 1
    y = - 1 + 3
    y = 2
    a = x = - 1
    b = y = 2
    nilai 3a + 3b = 3(-1) + 3(2) = - 3 + 6 = 3 ( C )

    5) x = 5
    y - 3x - 12 = 0
    y - 3(5) - 12 = 0
    y - 15 - 12 = 0
    y - 27 = 0
    y = 27
    hp = ( 5 , 27 ) ( D )