1. 2(x - 3) < 4(x - 2) = 2. -2 ≤ x + 3 ≤ 5 = 3. 2x/3 - 1/3 > 3x/4 = 4. 4(y - 5) < 2(4 - 3y) + 2 = 5. 7y > 5y + 4 =
Matematika
reaalpcy
Pertanyaan
1. 2(x - 3) < 4(x - 2) =
2. -2 ≤ x + 3 ≤ 5 =
3. 2x/3 - 1/3 > 3x/4 =
4. 4(y - 5) < 2(4 - 3y) + 2 =
5. 7y > 5y + 4 =
2. -2 ≤ x + 3 ≤ 5 =
3. 2x/3 - 1/3 > 3x/4 =
4. 4(y - 5) < 2(4 - 3y) + 2 =
5. 7y > 5y + 4 =
1 Jawaban
-
1. Jawaban AnugerahRamot
1.]
2(x - 3) < 4(x - 2) [bagi 2 kedua ruas]
x - 3 < 2x - 4
1 < x
x > 1
HP : {x | x > 1 , x ∈ R}
2.]
-2 ≤ x + 3 ≤ 5
-2 - 3 ≤ x + 3 - 3 ≤ 5 - 3
-1 ≤ x ≤ 2
HP : {x | -1 ≤ x ≤ 2 , x ∈ R}
3.]
⅔ x - ⅓ > ¾ x [ × 12 kedua ruas ]
8x - 4 > 9x
-4 > x
x < -4
HP : {x | x < -4 , x ∈ R}
4.]
4(y - 5) < 2(4 - 3y) + 2 [bagi 2 kedua ruas]
2y - 10 < 4 - 3y + 1
5y < 15
y < 3
HP : {y | y < 3 , y ∈ R}
5.]
7y > 5y + 4
2y > 4
y > 2
HP : {y | y > 2 , y ∈ R}