(10k)²= (2y - 3)³= (3a - 4b) ² = (2x - 4)³=
Matematika
ketutsudiarta46
Pertanyaan
(10k)²=
(2y - 3)³=
(3a - 4b) ² =
(2x - 4)³=
(2y - 3)³=
(3a - 4b) ² =
(2x - 4)³=
1 Jawaban
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1. Jawaban AkinariAihara
a) (10k)² = 100k²
b) (2y - 3)³ menggunakan segitiga pascal
= (2y)³ + 3(2y)²(-3) + 3(2y)(-3)² + (-3)³
= 8y³ + 3(4y²)(-3) + (6y)(9) + (-27)
= 8y³ - 36y² + 54y - 27
c) (3a - 4b)²
= (3a - 4b) (3a - 4b)
= 9a² - 12ab - 12ab + 16b²
= = 9a² - 24ab + 16b²
d) (2x - 4)³ menggunakan segitiga pascal
= (2x)³ + 3(2x)²(-4) + 3(2x)(-4)² + (-4)³
= 8x³ + 3(4x²)(-4) + (6x)(16) + (-64)
= 8x³ - 48x²) + 96x - 64