Matematika

Pertanyaan

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2 Jawaban


  • [tex] \frac{ \frac{x}{y} - \frac{y}{x} }{ \frac{2y}{x} - \frac{2x}{y} } \\ = \frac{ \frac{y^{2} - x^{2} }{xy} }{ \frac{2y ^{2} - 2x ^{2} }{xy} } \\ = \frac{y ^{2} - x ^{2} }{xy} \div \frac{2y^{2} - 2x ^{2} }{xy} \\ = \frac{y ^{2} - x ^{2} }{xy} \times \frac{xy}{2(y ^{2} - x^{2} ) } \\ = \frac{1}{1} \times \frac{1}{2} \\ = \frac{1}{2} [/tex]

    Jawaban : a. ½

    Maaf Kalau Salah
  • x/y-y/x / 2y/x-2x/y
    = y^2-x^2/xy / 2y^2-2x^2/xy
    = y^2-x^2/xy : 2y^2-2x^2/xy
    = y^2-x^2/xy × xy/2(y^2-x^2)
    = 1/1 × 1/2
    = 1/2 ----- A

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